4d N = 1 $$ \mathcal{N}=1 $$ from 6d N = 1 0 $$ \mathcal{N}=\left(1,0\right) $$ on a torus with fluxes (2017)

First Author: Bah I
Attributed to:  M-Theory, Cosmology and Quantum Field Theory funded by STFC

Abstract

No abstract provided

Bibliographic Information

Digital Object Identifier: http://dx.doi.org/10.1007/jhep06(2017)022

Publication URI: http://dx.doi.org/10.1007/jhep06(2017)022

Type: Journal Article/Review

Parent Publication: Journal of High Energy Physics

Issue: 6

ISSN: 1029-8479